Wednesday, 6 May 2015

Speed Concepts (Overtaking)

Given: Headstart Time, Chasing Time, Slow Speed
Answer: Fast Speed
At 10.30 a.m., a cyclist started travelling on a road at an average speed of 30 km/h. At 2.30 p.m., a motorist started from the same place, travelling on the same road. If the motorist took 4 h to catch up with the cyclist, find his average speed.

Cyclist Time = 
Cyclist Distance = 8 h x 30km/h = 240km
240km / 4 h = 60 km/h

Jon started cycling from Point A to Point B at 7 a.m. at an average speed of 12 km/h. David started cycling from Point A to Point B 3 hours later. Jon’s speed is twice of David’s.
At what time were the two cyclists 48 km apart?


At 12pm, Cleavon drove from Town A to Town B at a constant speed.
2 hours later, Sebastian also left Town A for Town B, driving at a certain speed which he kept constant throughout his journey.
At 5pm, Sebastian overtook Cleavon.
Sebastian's speed was 32km/h more than that of Cleavon's.
What was Cleavon's driving speed?

Rahan and Jim cycled from Point A to Point B. Rahan set off at 07 30. 30 minutes later, Jim set off and cycled at speed of 22 km/h. When Rahan reached Point B at 10 30, Jim was 8 km behind him. Find Rahan`s cycling speed.

Rahan's Time = 10 30 - 07 30 = 3 h
Jim's Time = 3 h - 1/2 h = 2 1/2 h
Jim's Distance = 22 km/h x 2 1/2 h = 55 km
Rahan's Distance = 55 km + 8 km = 63 km
Rahan's Speed = 63 km / 3 h = 21 km/h





Sam and Raju took part in a cycling race. Sam`s speed was 6 km/h slower than Raju. When Raju completed the race in 2 hours, Sam had only cycled 4/5 of the distance.
a) Find the distance of the race.
b) Find Raju`s speed


Difference in Distance = 6 km/h x 2 h = 12 km
Total Distance = 12 x 5 = 60 km

Raju's Speed = 60 km / 2 h = 30 km/h


Given: Triple Subjects


Ahmad, Bernard and Charlie were standing in a straight line waiting for the race to start. Charlie was 300 m ahead of Bernard and Bernard was 100 m ahead of Ahmad. At 9 a.m., they started the race. Ahmad overtook Bernard in 5 minutes. In another 5 minutes, Ahmad overtook Charlie. If Bernard's speed is 150 m/min, at what time did Bernard overtake Charlie?


(Ahmad Vs. Bernard)

Overtaking Speed = 100 m / 5 min = 20 m/min
Ahmad's Speed = 150 m/min + 20 m/min = 170 m/min

(Ahmad Vs. Charlie)

Overtaking Distance = 100 m + 300 m = 400 m
Overtaking Time = 5 min + 5 min =10 min
Overtaking Speed = 400 m / 10 min = 40 m/min
Charlie's Speed = 170 m/min - 40 m/min = 130 m/min

(Bernard Vs. Charlie)
Overtaking Speed = 150 m/min - 130 m/min = 20 m/min
Overtaking Time = 300 m / 20 m/min = 15 min

Given: Total Distance 
The distance between Town A and Town B is 116 km. A bus left Town A and headed for Town B. Some time later, a car left Town A and headed for Town B. Along the way, the car overtook the bus and arrived at Town B 45 minutes earlier than the bus. When the car arrived at Town B, the bus had travelled 5/8 of the distance. What was the speed of the car?


Bus's Remaining Distance = 3/8 of Total Distance = 43.5 km
Bus's Remaining Time = 45 min = 3/4 h
Bus's Speed = 43.5 km / 3/4h = 58 km/h
Bus Total Time = 116 km / 58 km/h = 2h
5/8 of Distance = 72.5 km
Car's Meeting to End Point Time = 72.5km / 48 km/h
(faulty answer)


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