The figure below is not drawn to scale. Given that TP = SP, find ∠RTS
TRS = 40 + 24 = 64 (exterior angle = interior opposite angles of triangle TPR)
TSP = (180 - 24) / 2 = 78 (base angles of isosceles triangle TSP)
RTS = 180 - 78 - 64 = 38 (angle sum of triangle RTS)
TRP = 180 - 40 - 24 = 116 (angle sum of triangle TRP)
TSP = (180 - 24) / 2 = 78 (base angles of isosceles triangle TSP)
RTS = 116 - 78 = 38 (exterior angle = interior opposite angles of triangle RTS)
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